The number of unpaired electrons in $C u^{+}$ $(a t o m i c n u m b e r = 29)$ is:

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Solution

The correct option is C \N
The ground state electronic configuration of $C u$ is
$= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{10}$

Thus the electronic configuration of $C u^{+}$ is
$= 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10}$

Since all orbitals are completely filled, the number of unpaired electron in $C u^{+}$ is zero

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Similar questions

C u^{+}

(a t o m i c n u m b e r = 29)

(a t o m i c n u m b e r = 24)

{C u}^{+}

d

{C u}^{+}

= 29

(- \frac{1}{2})

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