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Question

The number of values of k for which the system of linear equations,
(k+2)x+10y=kkx+(k+3)y=k1
has no soution, is :

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is A 1
For no solution, a1a2=b1b2c1c2k+2k=10k+3kk1(k+2)(k+3)=10kk25k+6=0(k2)(k3)=0k=2,3If k=2, then both the lines becomes identical. So, k2k=3 is the only one value of k.

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