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Byju's Answer
Standard XII
Mathematics
Combination
The number of...
Question
The number of values of
r
satisfying the equation
69
C
3
r
−
1
−
69
C
r
2
=
69
C
r
2
−
1
−
69
C
3
r
is:
A
1
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B
2
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C
4
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D
7
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Solution
The correct option is
B
2
Solution:
69
C
3
r
−
1
−
69
C
r
2
=
69
C
r
2
−
1
−
69
C
3
r
or,
69
C
3
r
−
1
+
69
C
3
r
=
69
C
r
2
+
69
C
r
2
−
1
or,
70
C
3
r
=
70
C
r
2
Here,
3
r
=
r
2
or
3
r
+
r
2
=
70
(
∵
n
C
r
=
n
C
s
then
r
=
s
or
r
+
s
=
n
)
or,
3
r
=
r
2
or,
r
(
r
−
3
)
=
0
or,
r
=
0
which is not possible.
or
r
=
3
r
2
+
3
r
−
70
=
0
or,
(
r
−
7
)
(
r
+
10
)
=
0
or,
r
=
7
or
r
=
−
10
which is not possible.
The value of
r
satisfying the equation
=
3
,
7
Number of values of
r
satisfying the equation
=
2
Hence, B is the correct option.
Suggest Corrections
0
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