Question

The number of ways a pack of 52 cards can be divided among four players in 4 sets, three of them having 17 cards each and the fourth one just 1card is

• A. $\frac{52!}{(17!{)}^3}$
• B. $\frac{52!}{3.(17!{)}^3}$
• C. $\frac{52!}{3!(17!{)}^3}$
• D. $\frac{52!}{3{!}^3(17!)}$

Answer 1

The correct option is A $\frac{52!}{(17!{)}^3}$

Required number of ways ${=}^{52}{C}_{17}{\times }^{35}{C}_{17}{\times }^{18}{C}_{17}{\times }^1{C}_1=\frac{52!}{(17!{)}^3}$
Since persons are distinguishable