The number of ways in which $n$ distinct objects can be put into two different boxes is

n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2^{n}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 n^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2^{n}$
Given there are two boxes.
Thus each ball have two choice to be put.
Hence required number of ways is $2 \times 2 \times 2 \times . . . . . . . . . = 2^{n}$

Suggest Corrections

Similar questions

Q. The number of ways in which n distinct objects can be put into two different boxes so that no box remains empty is

Q. The number of ways in which n distinct objects can be put into two different boxes so that no box remains empty, is

Q. Find the total number of ways in which

30

distinct objects can be put into two different boxes so that no box remains empty.

Q. The number of ways in which n distinct objects can be put into two identical boxes so that no box remains empty is

The number of ways in which 2n different things can be divided equally into two distinct groups is $\frac{2 n!}{2 (n!)^{2}}$ (If order of the group is NOT important)

Join BYJU'S Learning Program

The number of ways in which n distinct objects can be put into two different boxes is

The correct option is C 2nGiven there are two boxes.Thus each ball have two choice to be put.Hence required number of ways is 2×2×2×.........=2n

The number of ways in which $n$ distinct objects can be put into two different boxes is

The correct option is C $2^{n}$
Given there are two boxes.
Thus each ball have two choice to be put.
Hence required number of ways is $2 \times 2 \times 2 \times . . . . . . . . . = 2^{n}$