Question

The number $\sqrt{5}$ lies between $2$ integers $a$ and $b$ such that $b-a=1$. Then $b+a=?$

Answer 1

We know,

$\sqrt{4}=2$ and $\sqrt{9}=3$.

Also, $4<5<9$ $⟹\sqrt{4}<\sqrt{5}<\sqrt{9}$

$⟹2<\sqrt{5}<3$ and $3-2=1$.

$\therefore \sqrt{5}$ lies between $a=2$ and $b=3$.

Then, $⟹b+a=3+2=5$.

Hence, the answer is $5$.