Question

The numbers $1$ to $10$ are each printed on a counter and the $10$ counters are placed in a bag. If one counter is picked at random, what is the probability that the number on it is an even number?

Answer 1

Step 1 Finding the favorable and total outcomes:

There are $10$ counters placed in a bag, so the total outcome is $10$.

Even numbers are the numbers which are divisible by $2$.

In the range $1$ to $10$, the numbers which are divisible by $2$ are:

$2,4,6,8,10$

So the number of favourable outcomes are $5$.

Step 2 Finding the probability that the drawn counter has an even number on it:

The formula for the probability is expressed as,

$Probability=\frac{Number of favorable outcomes}{Total number of outcomes}$

Substitute favorable number of outcomes as $5$ and the total number of outcomes as $10$.

$$\begin{gathered} \Rightarrow P\left(evennumber\right)=\frac{5}{10} \\ \therefore P\left(evennumber\right)=\frac{1}{2} \end{gathered}$$

Hence, the probability of even numbered counter from a bag of $10$ counters numbered $1$ to $10$ is $\frac{1}{2}$.