The numbers from 1 to 45 which are exactly visible by 3 are arranged in ascending order, minimum number being on the top, which would be at the ninth place from the top?
A
18
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B
21
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C
24
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D
27
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Solution
The correct option is D27 The numbers from 1 to 45 which is exactly divisible by 3 are
3,6,9,12,15,18,21,24,27,30,33,36,39,42,45 In this sequence 9th number from the beginning is 27.