The object at rest suddenly explodes into three parts with the mass ratio 2:1:1. The parts of equal masses move at right angles to each other with equal speed v. The speed of the third part after the explosion will be:
A
2v
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B
v/√2
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C
v/2
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D
√2v
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Solution
The correct option is Bv/√2 Using conservation of linear momentum: 0=m4v^j+m4v^i+m2(vx^i+vy^j) ⇒vx=−v2^i vy=−v2^j So, speed =v√2