The observations 29,32,48,50,x,x+2,72,78,84,95 are arranged in ascending order and their median is 63, then the value of x is
A
61
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B
62
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C
62.5
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D
63
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Solution
The correct option is C62 Given distribution is in ascending order and having number of terms 10 (even) Hence median is A.M of 5th and 6th terms =x+x+22=63 (given) ∴x=62