Question

The % of S in an organic compound whose 0.32g produces 0.233 g of BaSO4 is (Molar Mass of $BaS{O}_4$=233)

• A. 1
• B. 10
• C. 23.5
• D. 32.1

Answer 1

The correct option is B 10

$\%ofS=\frac{32\times \text{mass of}BaS{O}_4\times 100}{233\times \text{mass of compound}}=\frac{32\times 0.233\times 100}{233\times 0.32}=10$