Question

The only, most stable nucleus formed by bombarding either ${}_{13}^{27}Al$ by neutrons or ${}_{11}^{23}Na$ by deutrons is:

• A. ${}_{15}^{30}P$
• B. ${}_{14}^{30}Si$
• C. ${}_{12}^{24}Mg$
• D. ${}_{56}^{137}Ba$

Answer 1

The correct option is D ${}_{56}^{137}Ba$

$N_2\left(g\right)+3H_2\left(g\right)\stackrel{Fe}{\to }2N{H}_3\left(g\right)\Delta H=-22.4kJ/mol$

at $t=0$ $30lt$ $30lt$ $0$

at $b=t$ $(30-10)lt$ $(30-30)lt$ $20lt$

But according to question $50\%$ yield $30$

final volume abstained $=10lt$ of $N{H}_3$

$N_2\left(g\right)+3H_2\to 2N{H}_3\left(g\right)$

$30-5lt$ $30-15lt$ $10-lt$ of

$=25H$ $=15lt$ $N{H}_3$

of $N_2$ of $H_2$

$vo{l}^m$ of $N_2=25Lt$

$vo{l}^m$ of $H_2=15lt$

$vo{l}^m$ of $N{H}_3=10lt$