The orange solid on heating gives a colorless gas and a green solid which can be reduced to metal by aluminum powder. The orange and the green solids are, respectively:

({N H}_{4})_{2} {C r}_{2} O_{7}

and

{C r}_{2} O_{3}

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{N a}_{2} {C r}_{2} O_{7}

and

{C r}_{2} O_{3}

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K_{2} {C r}_{2} O_{7}

and

C r O_{3}

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{({N H}_{4})}_{2} C r O_{4}

and

C r O_{3}

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Solution

The correct option is B $({N H}_{4})_{2} {C r}_{2} O_{7}$ and ${C r}_{2} O_{3}$
Orange solid is ammonium dichromate
${({N H}_{4})}_{2} {C r}_{2} O_{7} o r a n g e s o l i d Δ - \to N_{2} c o l o u r l e s s g a s ↑ + {C r}_{2} O_{3} g r e e n s o l i d + 4 H_{2} O$
${C r}_{2} O_{3} + 2 A l ⟶ 2 C r + {A l}_{2} O_{3}$

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Similar questions

{N a}_{2} S_{2} O_{3}

K_{2} {C r}_{2} O_{7}

K_{2} {C r}_{2} O_{7}

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K_{2} {C r}_{2} O_{7} + x H_{2} S O_{4} + y S O_{2} ⟶ K_{2} S O_{4} + {C r}_{2} {(S O_{4})}_{3} + z H_{2} O

x, y

z

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