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Byju's Answer
Standard XII
Physics
Hydrogen Spectra
The orbit num...
Question
The orbit number for a circular orbit of diameter 20 nm for the hydrogen atom is:
A
10
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B
14
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C
12
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D
16
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Solution
The correct option is
B
14
Bohr radius is given as,
r
n
=
0.529
n
2
×
10
−
10
m
.
Given that, diameter
=
20
n
m
∴
Radius
=
10
n
m
=
10
×
10
−
9
m
Using Bohr radius equation:
n
2
=
10
×
10
−
9
0.529
×
10
−
10
=
100
0.529
⇒
n
≈
14
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1
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