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Byju's Answer
Standard XIII
Chemistry
Quantum Numbers
The orbital a...
Question
The orbital angular momentum of a 4p electron will be :
A
4
h
2
π
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B
√
2
h
2
π
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C
√
6
h
4
π
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D
√
2
h
4
π
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Solution
The correct option is
B
√
2
h
2
π
For p-orbital,
l
=
1
where
l
=
Azimuthal quantum number
Orbital angular momentum is given by
L
=
h
2
π
√
l
(
l
+
1
)
Putting the value of
l
, we get
L
=
h
2
π
√
1
(
1
+
1
)
=
√
2
h
2
π
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