Question

The orbital angular momentum of an electron corresponding to $n=4$ and $m=-3$ is:

• A. $0$
• B. $\frac{h}{\sqrt{2}\pi }$
• C. $\frac{\sqrt{6}h}{2\pi }$
• D. $\frac{\sqrt{3}h}{\pi }$

Answer 1

The correct option is D $\frac{\sqrt{3}h}{\pi }$

The orbital angular momentum of an electron in a subshell with azimuthal quantum number$\left(l\right)$ is given by,

$L=\frac{h}{2\pi }\sqrt{l(l+1)}$

Hence, for $n=4$ and $m=-3$ corresponding value of azimuthal quantum number $l=3$.

Therefore, $L=\frac{h}{2\pi }\sqrt{12}=\frac{\sqrt{3}h}{\pi }$