Question

The orbital angular momentum of an electron in 2$s^{-}$ orbital is

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Since s-orbital have l = 0

Angular momentum = $\sqrt{l(l+1)}$ $\times$ $\frac{h}{2\pi }$

= 0 $\times$ $\frac{h}{2\pi }$ = 0