Question

The orbital angular momentum of an electron in 2 s-orbital is :

• A. $+\frac{1}{2}\frac{h}{2\pi }$
• B. Zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

Answer: (B)

Zero

Orbital angular mometum $=\sqrt{l(l+1)}\cdot \frac{h}{2\pi }$
For 2 s-orbital, $l=0$
$\therefore$ Orbital angular momentum $=\sqrt{0(0+1)}\frac{h}{2\pi }=$ zero.