Question

The orbital angular momentum of an electron in $2s$-orbital is:

• A. $\frac{h}{4\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

The correct option is B zero

The orbital angular momentum of an electron in the 2s-orbital is zero.

For a given subshell with azimuthal quantum number l, the orbital angular momentum is given by the expression

$L=\frac{h}{2\pi }\sqrt{l(l+1)}$
For 2s orbital, $l=0$ so $L=\frac{h}{2\pi }\sqrt{0(0+1)}=0$

So, the correct option is $B$