Question

The orbital angular momentum of an electron in $p$-orbital is:

• A. Zero
• B. $\frac{h}{\sqrt{2}\pi }$
• C. $\frac{h}{2\pi }$
• D. $\frac{1}{2}\frac{h}{2\pi }$
• E. $\frac{h}{2\sqrt{2}\pi }$

Answer 1

Answer: (B)

$\frac{h}{\sqrt{2}\pi }$

The orbital angular momentum of an electron in p-orbital is $\frac{h}{\sqrt{2}\pi }$

${\mu }_L=\sqrt{l(l+1)}\frac{h}{2\pi }$

For a p orbital, $l=1$

Hence,

${\mu }_L=\sqrt{1(1+1)}\frac{h}{2\pi }$

${\mu }_L=\sqrt{2}\frac{h}{2\pi }$

${\mu }_L=\frac{h}{\sqrt{2}\pi }$