Question

The orbital angular momentum of an electron is $2s$ orbital is:

• A. $+\frac{1}{2}\cdot \frac{h}{2\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\cdot \frac{h}{2\pi }$

Answer 1

Answer: (B)

zero

Orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }=0$

($because$ for $2$s-electron, $l=0$).

Hence, option B is correct.