Question

The orbital represented by ${\psi }_{4,2,0}$ is:

• A. $4d_{z^2}$
• B. $4p_x$
• C. $4p_z$
• D. $4d_{xy}$

Answer 1

The correct option is A $4d_{z^2}$

As we know,
wavefunction is represented as
${\psi }_{n,l,m}$ so here,
${\psi }_{4,2,0}$ means $n=4,l=2,m=0$
$\therefore 4d_{z^2}$ (as this orbital has these quantum values)