The order of a column matrix can be

2 x 2

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1 x 2

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3 x 1

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3 x 2

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Solution

The correct option is C
3 x 1

Remember a column matrix contains one column and m number of rows where m can be any natural number. Here the only option which satisfies this is 3 $\times$ 1 where number of column is one.

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Similar questions

∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + x & 2 & 3 & 4 1 & 2 + x & 3 & 4 1 & 2 & 3 + x & 4 1 & 2 & 3 & 4 + x \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣

= x^{3} (x + 10)

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} - 1, & x < - 1 x^{3}, & - 1 \leq x \leq 1 1 - x, & 1 < x < 2 3 - x^{2} & x > 2 \end{matrix}

∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{3} & {3 x}^{2} & 3 x & 1 x^{2} & x^{2} + 2 x & 2 x + 1 & 1 x & 2 x + 1 & x + 2 & 1 1 & 3 & 3 & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ = {(x - 1)}^{6} .

Δ = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & x & x^{2} x & x^{2} & 1 x^{2} & 1 & x \end{matrix} ∣ ∣ ∣ ∣ ∣ = - 7

Δ_{1} = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{3} - 1 & 0 & x - x^{4} 0 & x - x^{4} & x^{1} - 1 x - x^{4} & x^{3} - 1 & 0 \end{matrix} ∣ ∣ ∣ ∣ ∣

x \in R

⎡ ⎢ ⎣ \begin{matrix} x 2 x 3 x \end{matrix} \begin{matrix} x^{2} 4 x^{2} 9 x^{2} \end{matrix} \begin{matrix} 1 + x^{3} 1 + 8 x^{3} 1 + 27 x^{3} \end{matrix} ⎤ ⎥ ⎦ = 10

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