The order of acidic strength of $H O C l, H C l O_{2}, H C l O_{3}$ and $H C l O_{4}$ are:

H C l O_{4} > H C l O_{3} > H C l O_{2} > H C l O

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H C l O > H C l O_{2} > H C l O_{3} > H C l O_{4}

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H C l O_{3} > H C l O_{4} > H C l O_{2} > H C l O

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H C l O_{3} > H C l O_{2} > H C l O > H C l O_{4}

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Solution

The correct option is A $H C l O_{4} > H C l O_{3} > H C l O_{2} > H C l O$
Oxygen is more electronegative than chlorine. With an increase in the number of $O$ atoms attached to $C l$ , more electrons are pulled away from $O - H$ bond and more weaker becomes the $O - H$ bond. This increases the acid strength.
The decreasing order of acidic strength is $H C l O_{4} > H C l O_{3} > H C l O_{2} > H C l O$ .

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O

H C l O, H C l O_{2}, H C l O_{3}, H C l O_{4}

H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

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