The order of dipole moment of the above molecules is

I > II > III > IV

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II > I > III > IV

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II > III > I > IV

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II > I > III > IV

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Solution

The correct option is D
II > I > III > IV

Ortho-describes a molecule with substituents at the 1 and 2 positions on an aromatic compound.Para- describes molecule with substituents at the 1 and 4 positions on an aromatic compound.Para compound has zero dipole moment and ortho compound has maximum value.

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Similar questions

In the following molecules:
$C H_{3} B r, C H_{3} F, C H_{3} C l, C H_{3} I I, I I, I I I, I V$
The correct order of dipole moment will be:

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

- S O_{3} H

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

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