The order of reactivity of following alcohols with halogen acids is?
(I) $C H_{3} C H_{2} C H_{2} O H$
(II) $C H_{3} - C H_{2} - C | O H H - C H_{3}$
(III) $C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H$

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Solution

The order of reactivity of alcohols with halogen acids is $T e r t i a r y > S e c o n d a r y > P r i m a r y$
By that logic, the order of reactivity of the given alcohols in decreasing order is $(I I I) > (I I) > (I)$

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