The order of screening effect of electrons of $s, p, d$ and $f$ orbitals of a given shell of an atom on its outer shell electrons is:

s > p > d > f

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f > d > p > s

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p > f > d > s

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f > p > s > d

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Solution

The correct option is A $s > p > d > f$
For the same shell, screening effect decreases in the order: $s > p > d > f$ . Thus, for $n = 4$ , $4 s$ orbital has maximum screening effect and $4 f$ orbital has the lowest screening effect.

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The order of screening effect of electrons of s, p, d and f orbitals of a given shell of an atom on its outer shell electrons is:

The correct option is A s>p>d>fFor the same shell, screening effect decreases in the order: s>p>d>f. Thus, for n=4, 4s orbital has maximum screening effect and 4f orbital has the lowest screening effect.

The order of screening effect of electrons of $s, p, d$ and $f$ orbitals of a given shell of an atom on its outer shell electrons is:

The correct option is A $s > p > d > f$
For the same shell, screening effect decreases in the order: $s > p > d > f$ . Thus, for $n = 4$ , $4 s$ orbital has maximum screening effect and $4 f$ orbital has the lowest screening effect.