Question

The order of size of nucleus and Bohr’s radius of an atom respectively are:

• A. ${10}^{-14}m,{10}^{-10}m$
• B. ${10}^{-10}m,{10}^{-8}m$
• C. ${10}^{-20}m,{10}^{-16}m$
• D. ${10}^{-8}m,{10}^{-6}m$

Answer 1

The correct option is A ${10}^{-14}m,{10}^{-10}m$

Bohr radius is nearly $0.539\times {10}^{-10}$ m and diameter of nucleus is in the range $1.75\times {10}^{-15}$ m.

Thus order of size of nucleus and Bohr radius of an atom is ${10}^{-14}$ m and ${10}^{-10}$ m, respectively.