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Question

The order of stability of the alkenes R2C=CR2I,R2C=CHRII,R2C=CH2III,RCH=CHRIV, and RCH=CH2V is:

A
I > II > III > IV > V
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B
I = II > III > IV > V
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C
II > I > IV > III > V
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D
V > IV > III > I > II
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Solution

The correct option is A I > II > III > IV > V
The order of stability of alkenes is as follows:
R2C=CR2(I)>R2C=CHR(II)>R2C=CH2(III)>RCH=CHR(IV)>RCH=CH2(V)

This order of stability is due to hyper conjugation.
Hyper conjugation: The stabilizing interaction that results from the interaction of the electrons in a σ-bond (usually CH or CC) with an adjacent empty or partially filled p-orbital or a π-orbital to give an extended molecular orbital that increases the stability of the system.

So answer is A.

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