The order of stability of the following carbocations

III>II>I

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II>III>I

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I>II>III

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III>I>II

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Solution

The correct option is D III>I>II

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Similar questions

The correct order for decreasing stability of the following free radicals is

^{\oplus} C H_{2} - C O C H_{3}

^{\oplus} C H_{2} - O C H_{3}

^{\oplus} C H_{2} - C H_{3}

The stability of carbanions in the following

i) $R C \equiv ⊖ C$

ii)

iii) $R_{2} C = ⊖ C H$

iv) $R_{3} C - ⊖ C H_{2}$

is in the order of

I V > I I I > I I > I

I V > I I I > I > I I

I V > I > I I > I I I

(I) H_{2} C = + N = - N

(I I) H_{2} + C - N = - N

(I I I) H_{2} - C - + N \equiv N

(I V) H_{2} - C - N = + N

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