The order of the oxidation state of the phosphorous atom in $H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}$ and $H_{4} P_{2} O_{6}$ is:

H_{3} P O_{3} > H_{3} P O_{2} > H_{3} P O_{4} > H_{4} P_{2} O_{6}

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H_{3} P O_{4} > H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6}

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H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}

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H_{3} P O_{2} > H_{3} P O_{3} > H_{4} P_{2} O_{6} > H_{3} P O_{4}

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Solution

The correct option is C $H_{3} P O_{4} > H_{4} P_{2} O_{6} > H_{3} P O_{3} > H_{3} P O_{2}$
$\begin{matrix} Species & Oxidation state of P H_{3} P O_{4} & + 5 H_{4} P_{2} O_{6} & + 4 H_{3} P O_{3} & + 3 H_{3} P O_{2} & + 1 \end{matrix}$

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Similar questions

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

H_{4} P_{2} O_{6}

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

H_{4} P_{2} O_{6}

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

H_{4} P_{2} O_{6}

H_{3} P O_{4}, H_{3} P O_{3}, H_{3} P O_{2}, H C l O, H_{4} P_{2} O_{6}, H_{2} S_{2} O_{6}

H_{3} P O_{4}, H_{3} P O_{3}

H_{3} P O_{2}

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