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Ores and Minerals

The ore chrom...

Question

The ore chromite is:

F e {C r}_{2} O_{4}

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C o {C r}_{2} O_{3}

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C r {F e}_{2} O_{4}

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F e {C r}_{2} O_{3}

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Solution

The correct option is A $F e {C r}_{2} O_{4}$
The formula for Ore chomite is $F e {C r}_{2} O_{4}$ ,
Hence option A is the correct answer.

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Similar questions

F e {C r}_{2} O_{4}

C r

I \to {N a}_{2} C r O_{4} I I - \to {C r}_{2} O_{3} I I I - - \to C r

I, I I

I I I

F e {C r}_{2} O_{4} + {N a}_{2} {C O}_{3} + O_{2} F u s i o n - --- \to [X] H^{+} - - \to H_{2} O [Y] H^{+} - -- \to H_{2} O_{2} [Z]

[X], [Y]

[Z]

Δ G = - 177 K c a l

(1) 2 F e (s) + \frac{3}{2} O_{2} (g) ⟶ {F e}_{2} O_{3} (s)

Δ G = - 19 K c a l f o r (2) {4 F e}_{2} O_{3} (s) ⟶ {3 F e}_{3} O_{4} (s)

{F e}_{3} O_{4}

(C_{9} H_{8} O_{4})

(C_{7} H_{6} O_{3})

(C_{4} H_{6} O_{3})

C_{7} H_{6} O_{3} + C_{4} H_{6} O_{3} \to C_{9} H_{8} O_{4} + C_{2} H_{4} O_{2}

F e {C r}_{2} O_{4}

N a O H

K C l

8 M n O_{4}^{-} + 3 S_{2} O_{3}^{2 -} + H_{2} O \to

{C r}_{2} O_{7}^{2 -} + 3 {S n}^{2 +} + 14 H^{+} \to

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