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Question

The osmotic pressure of equimolar solutions of BaCl2, NaCl and glucose will be in the order:


A

Glucose>NaCl>BaCl2

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B

BaCl2>NaCl>Glucose

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C

NaCl>BaCl2>Glucose

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D

NaCl>Glucose>Ba

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Solution

The correct option is B

BaCl2>NaCl>Glucose


Explanation for correct option

(B)BaCl2>NaCl>Glucose

Osmotic pressure

  • The flow of the solvent from its side to the solution side across a semipermeable membrane can be stopped if some extra pressure is applied on the solution. This pressure that just stops the flow of solvent is called osmotic pressure of the solution.
  • Osmotic pressure is a colligative property.
  • The expression for osmotic pressure is as follows:-
  • π=iCRT
  • Here, π is the osmotic pressure, i, known as the van’t Hoff factor, to account for the extent of dissociation or association, C is the concentration, R is the gas constant, and T is the temperature.
  • The dissociation of BaCl2 is as follows:-
  • BaCl2Ba2++2Cl-
  • So, the value of van't hoff factor is 3.
  • The dissociation of NaCl is as follows:-
  • NaClNa++Cl-
  • So, the value of van't hoff factor is 2.
  • The value of van't Hoff factor for glucose is 1 because it does not give any ions in the solution.
  • Hence, the order of osmotic pressure of equimolar solutions of BaCl2, NaCl and glucose is as follows:-
  • BaCl2>NaCl>Glucose

Explanation for incorrect option

The order of osmotic pressure of equimolar solutions of BaCl2, NaCl and glucose is BaCl2>NaCl>Glucose. Hence, options (A), (C), and (D) are incorrect.

Hence, option (B) is correct. The order of osmotic pressure of equimolar solutions of BaCl2, NaCl and glucose is BaCl2>NaCl>Glucose.


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