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Osmotic Pressure

The Osmotic p...

Question

The Osmotic pressure of solution containing $4.0 g$ of solute $(m o l a r m a s s 246)$ per liter at $27^{o} C$ is : $(R = 0.082 L a t m k^{- 1} m o l^{- 1})$

0.1 a t m

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0.2 a t m

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0.4 a t m

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0.8 a t m

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Solution

The correct option is C $0.4 a t m$
Here answer is option $C$
$π = \frac{W}{M \times V} \times R \times T$
$= (\frac{4.0}{246 \times 1 L}) \times 300 K \times 0.0821$
$= 0.4$ atm

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Similar questions

27^{o} C

[R = 0.0822 a t m L {m o l}^{- 1}]

(in L)

1 g mole

1 atm

27^{\circ} C

R = 0.082 {L atm K}^{- 1} {mol}^{- 1}

27^{o} C

K^{- 1} m o l^{- 1}

4 g

100 m L

500 c m

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300 c m^{3}

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300 c m^{3}

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20^{o} C

R = 0.082 L a t m K^{- 1} m o l^{- 1}

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