The outer electronic configuration of transitional elements is:

(n - 1) s^{2} n d^{1 - 2}

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(n + 1) s^{2} n d^{1 - 5}

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(n - 1) s^{2} n p^{6} (n - 1) d^{1 - 10} n s^{1, 2}

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n s^{2} (n - 1) d^{1 - 10}

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Solution

The correct option is B $(n - 1) s^{2} n p^{6} (n - 1) d^{1 - 10} n s^{1, 2}$
Electronic configuration of transition elements
$(n - 1) s^{2} p^{6} (n - 1) d^{1 - 10} n s^{1 - 2}$

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Similar questions

(n - 1) d^{1 - 10} n s^{1 - 2}

The outer electron configuration of first transition series is ${(n - 1) d}^{1 - 10} {n s}^{1 - 2}$ . Then value of $n$ is:

(n - 1) d^{1 - 10} n s^{1 - 2}

n s^{2} (n - 1) d^{1 - 10} (n - 2) f^{1 - 14}

(n - 1) d^{1} {n s}^{2}

n = 4

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