The outer measurements of a closed wooden box are 45 cm - 32 cm - 28 cm- if the box is made of wood 1 cm thick the capacity of the box-

Since the wood is 1 cm thick, the inner measurements of the box are #160; ( 45 2 )cm× ( 32 2 )cm× ( 28 2 )cm .i.e. #160; 43× 30× 26cm^2=33540cm^2 ...

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Standard IX

Mathematics

Volume of a cuboid

The outer mea...

Question

The outer measurements of a closed wooden box are $45$ cm $\times 32$ cm $\times 28$ cm, if the box is made of wood $1$ cm thick the capacity of the box.

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Solution

Since the wood is 1 cm thick, the inner measurements of the box are $(45 - 2) c m \times (32 - 2) c m \times (28 - 2) c m$ .
i.e. $43 \times 30 \times 26 c m^{2} = 33540 c m^{2}$
Hence capacity of the box = inner volume of the box
$= 33540 c m^{3}$

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The outer measurements of a closed wooden box are 45 cm ×32 cm ×28 cm, if the box is made of wood 1 cm thick the capacity of the box.

Since the wood is 1 cm thick, the inner measurements of the box are (45−2)cm×(32−2)cm×(28−2)cm.i.e. 43×30×26cm2=33540cm2Hence capacity of the box = inner volume of the box=33540cm3

The outer measurements of a closed wooden box are $45$ cm $\times 32$ cm $\times 28$ cm, if the box is made of wood $1$ cm thick the capacity of the box.

Since the wood is 1 cm thick, the inner measurements of the box are $(45 - 2) c m \times (32 - 2) c m \times (28 - 2) c m$ .
i.e. $43 \times 30 \times 26 c m^{2} = 33540 c m^{2}$
Hence capacity of the box = inner volume of the box
$= 33540 c m^{3}$