Question

The oxidation number of $C$-atom in $C{H}_2{Cl}_2$ and $C{Cl}_4$ are respectively :

• A. $-2$ and $-4$
• B. $0$ and $-4$
• C. $0$ and $4$
• D. $2$ and $4$

Answer 1

Answer: (C)

$0$ and $4$

Oxidation number of carbon in $C{H}_{2}C{l}_2$ is

$0=x+2(+1)+2(-1)$

$0=x+2-2$

$0=x+0$

$x=0$

Oxidation number of carbon in $CC{l}_4$ is $+4$.

Hence, option C is correct.