Question

The oxidation number of C atom in $C{H}_{2}C{l}_2$ and $CC{l}_4$ are respectively :

• A. $-2$ and $-4$
• B. $0$ and $-4$
• C. $0$ and $4$
• D. $2$ and $4$

Answer 1

The correct option is C $0$ and $4$

Let the oxidation number of C be $x$.

In $C{H}_{2}C{l}_2$, the oxidation number of $C$ atom is:
$x+2(+1)+2(-1)=0$
$x+2-2=0$
$x=0$

In $CC{l}_4$, the oxidation number of $C$ atom is:
$x+4(-1)=0$
$x-4=0$
$x=4$

Hence, option $C$ is correct.