Question

The oxidation number of carbon is zero in :

• A. $HCHO$
• B. $C{H}_{2}C{l}_2$
• C. $C_6{H}_{12}{O}_6$
• D. All of the above

Answer 1

The correct option is D All of the above

Let, the oxidation number of $Cbex$
We know that,
Oxidation number of $H=+1$
Oxidation number of $Cl=-1$
Oxidation number of $O=-2$
(A) $HCHO$
$+1+x+1+(-2)=0$
$x=0$
(B) $C{H}_{2}C{l}_2$
$x+(2\times 1)+(2\times -1)=0$
$x=0$
(C) $C_6{H}_{12}{O}_6$
$6x+(1\times 12)+(-2\times 6)=0$
$x=0$
Hence, Carbon is in zero oxidation state in all the given compounds.