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Question

The oxidation number of Cr is +6 in :

A
FeCr2O4
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B
KCrO3Cl
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C
CrO5
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D
[Cr(OH)4]
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Solution

The correct options are
B KCrO3Cl
C CrO5
a. Fe+2(Cr2O4)2: Oxidation state of Cr=+3
b. K[CrO3Cl]: Oxidation state of Cr=+6
c. CrO5 : Oxidation state of Cr=+6 (Two peroxo linkage)
d. [Cr(OH)4]: Oxidation state of Cr=+3
Hence, options B and C are correct.

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