CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The oxidation number of $$Cr$$ is $$+6$$ in :


A
FeCr2O4
loader
B
KCrO3Cl
loader
C
CrO5
loader
D
[Cr(OH)4]
loader

Solution

The correct options are
B $$KCr{ O }_{ 3 }Cl$$
C $$Cr{ O }_{ 5 }$$
a.  $${ Fe }^{ +2 }{ \left( { Cr }_{ 2 }{ O }_{ 4 } \right)  }^{ 2- }:$$ Oxidation state of $$Cr = +3$$
b.  $${ K }^{ \oplus  }{ \left[ Cr{ O }_{ 3 }Cl \right]  }^{ \ominus  }:$$ Oxidation state of $$Cr = +6$$
c.  $$CrO_5$$ : Oxidation state of $$Cr = +6$$ (Two peroxo linkage)
d.  $${ \left[ Cr{ \left( OH \right)  }_{ 4 } \right]  }^{ \ominus  }:$$ Oxidation state of $$Cr = +3$$
Hence, options B and C are correct.

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image