Question

# The oxidation number of $$Cr$$ is $$+6$$ in :

A
FeCr2O4
B
KCrO3Cl
C
CrO5
D
[Cr(OH)4]

Solution

## The correct options are B $$KCr{ O }_{ 3 }Cl$$ C $$Cr{ O }_{ 5 }$$a.  $${ Fe }^{ +2 }{ \left( { Cr }_{ 2 }{ O }_{ 4 } \right) }^{ 2- }:$$ Oxidation state of $$Cr = +3$$b.  $${ K }^{ \oplus }{ \left[ Cr{ O }_{ 3 }Cl \right] }^{ \ominus }:$$ Oxidation state of $$Cr = +6$$c.  $$CrO_5$$ : Oxidation state of $$Cr = +6$$ (Two peroxo linkage)d.  $${ \left[ Cr{ \left( OH \right) }_{ 4 } \right] }^{ \ominus }:$$ Oxidation state of $$Cr = +3$$Hence, options B and C are correct.Chemistry

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