The oxidation number of manganese in $K M n O_{4}$ is_________.

+ 3

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+ 5

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+ 7

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+ 9

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Solution

The correct option is D $+ 7$
$K M n O_{4}$ : Potassium permanganate
Let the oxidation state of $M n$ be $x$ .
Since the complex is neutral, sum of all oxidation states will be equal to zero.
Hence, $+ 1 + x - 8 = 0$ or, $x = + 7$

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