wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The oxidation number of Mn in the product of alkaline oxidative fusion of MnO2 is

Open in App
Solution

Reaction involved for the product of alkaline oxidative fusion of manganese dioxide

2MnO2 + 4KOH + O2 → K2MnO4 + 2H2O

Product : K2MnO4 or MnO4 2-

Thus oxidation state of Mn in MnO4 2-

X = Mn

X + 4 x (-2) = -2

X = 6

Mn exist in +6 State


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rules for Assigning Oxidation Number and State
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon