The oxidation number of Mn in the product of alkaline oxidative fusion of $M n O_{2}$ is ___

Open in App

Solution

The oxidation number of Mn in the product alkaline oxidative fusion of $M n O_{2}$ is 6.
$2 M n O_{2} + 4 K O H + O_{2} \to 2 K_{2} M n O_{4} + 2 H_{2} O$
In $K_{2} M n O_{4}$ , the oxidation state of Mn is +6

Suggest Corrections

Similar questions

M n

M n O_{2}

M n

M n O_{2}

M n

K M n O_{4}, K_{2} M n O_{4}, M n S O_{4}, M n O_{2}

{M n}_{3} O_{4}

M n

M n C l_{2}

M n (O H)_{3}

M n O_{2}

K M n O_{4}

M n

Join BYJU'S Learning Program