Question

The oxidation number of nitrogen atoms in $N{H}_{4}N{O}_3$ are:

• A. $+3,+3$
• B. $+3,-3$
• C. $-3,+5$
• D. $-5,+3$

Answer 1

The correct option is C $-3,+5$

$N{H}_{4}N{O}_3\rightleftharpoons N{H}_4^{+}+N{O}_3^{-}\text{In}N{H}_4^{+}x+4=+1\Rightarrow x=-3\text{In}N{O}_3^{-}x-6=-1x=+5$