The oxidation number of phosphorus in $M g_{2} P_{2} O_{7}$ is:

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-3

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Solution

The correct option is C 5
$M g_{2} P_{2} O_{7}$
Let x be the oxidation state of P,
Mg carries + 2 charge and each oxygen carries -2 charge
2(+2) + 2x + 7 (-2) = 0
$∴ x = + 5$

So, oxidation number of P = + 5

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