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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
The oxidation...
Question
The oxidation number of underlined element in
N
a
2
[
F
e
–
–
–
(
C
N
)
5
N
O
+
]
c
ompound is
:
A
2
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B
3
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C
1
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D
None of these
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Solution
The correct option is
A
2
In
N
a
2
[
F
e
(
C
N
)
5
N
O
+
]
the oxidation state of
F
e
is determined as follows:
N
a
has
+
1
O.S. , so
2
N
a
will give
2
+
charge.
Hence charge on complex is
−
2
.
Let
F
e
have O.S.
=
x
.
so
x
+
(
−
1
)
5
+
1
=
−
2
x
=
+
5
−
1
−
2
=
+
2
.
So,
F
e
has
+
2
oxidation state.
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