The oxidation numbers of C - 1 and C - 2 in propene $C H_{3}^{2} C H =^{1} C H_{2}$ are respectively

-1, -2

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-1, -1

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-2, -1

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+2, -1

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Solution

The correct option is C
-2, -1

$H - H | C | H - H | C^{(- 1)} | H$ = $^{(- 2)} C_{╲_{H}}^{╱^{H}}$

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