Question

The oxidation numbers of C - 1 and C - 2 in propene $C{H}_3{}^{2}CH={}^{1}C{H}_2$ are respectively

• A. -1, -2
• B. -1, -1
• C. -2, -1
• D. +2, -1

Answer 1

The correct option is C

-2, -1

$H-\stackrel{\underset{|}{H}}{\underset{\stackrel{|}{H}}{C}}-\stackrel{\underset{|}{H}}{\underset{\stackrel{|}{H}}{C^{(-1)}}}$=${}^{(-2)}{C}_{{╲}_H}^{{╱}^H}$