The oxidation of central atom in the complex $[C o (N H_{3})_{4} C l N O_{2}]$ is:

+ 2

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+ 3

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+ 1

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zero

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Solution

The correct option is D $+ 2$
$[C o (N H_{3})_{4} C l N O_{2}]$
$= [C o (N H_{3})_{4} C l N O_{2}]$
$= n - 2 = 0; n = 2$
So, the oxidation number $= + 2$

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Similar questions

The oxidation State of central atom in the complex $[C o (N H_{3}) 4 C l N O_{2}]$ is

	Column I ( Complex)		Column II ( Oxidation state of central atom )
(A)	$K_{3} [C O (C_{2} O_{4})_{2} C l_{2}]$	(i)	$0$
(B)	$[P t (C_{2} H_{4} C l_{3}]^{-}$	(ii)	$+ 1$
(C)	$[F e (H_{2} O)_{5} N O] S O_{4}$	(iii)	$+ 3$
(D)	$[N i (C O)_{4}]$	(iv)	$+ 2$

[F e (C o)_{5}]

_{3}

_{2}

_{2}

_{4}

^{Θ}

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